若 2a+log2a=4b+2log4b{2}^{a} + {\log }_{2}a = {4}^{b} + 2{\log }_{4}b2a+log2a=4b+2log4b ,则( )A. a>2ba > {2b}a>2b B. a<2ba < {2b}a<2b C. a>b2a > {b}^{2}a>b2 D. a<b2a < {b}^{2}a<b2