数列 {an}\left\{ {a}_{n}\right\}{an} 满足 a1∈[−1,1],an+1=2an2−1{a}_{1} \in \left\lbrack {-1,1}\right\rbrack ,{a}_{n + 1} = 2{a}_{n}^{2} - 1a1∈[−1,1],an+1=2an2−1 ,记 Tn=a1a2a3⋯an{T}_{n} = {a}_{1}{a}_{2}{a}_{3}\cdots {a}_{n}Tn=a1a2a3⋯an ,则 1−a12⋅T2025\sqrt{1 - {a}_{1}^{2}} \cdot {T}_{2025}1−a12⋅T2025 的最大值为___.