已知 sin(α−β)=13,cosαsinβ=16\sin \left( {\alpha - \beta }\right) = \frac{1}{3},\cos \alpha \sin \beta = \frac{1}{6}sin(α−β)=31,cosαsinβ=61 ，则 cos(2α+2β)=\cos \left( {{2\alpha } + {2\beta }}\right) =cos(2α+2β)= （ ）.A. 79\frac{7}{9}97B. 19\frac{1}{9}91C. −19- \frac{1}{9}−91D. −79- \frac{7}{9}−97