已知函数 f(x)=sin(2x+φ)(∣φ∣<π2)f\left( x\right) = \sin \left( {{2x} + \varphi }\right) \left( {\left| \varphi \right| < \frac{\pi }{2}}\right)f(x)=sin(2x+φ)(∣φ∣<2π) ,若存在 x1,x2,x3∈(0,3π2){x}_{1},{x}_{2},{x}_{3} \in \left( {0,\frac{3\pi }{2}}\right)x1,x2,x3∈(0,23π) , 且 x3−x2=2(x2−x1)=4x1{x}_{3} - {x}_{2} = 2\left( {{x}_{2} - {x}_{1}}\right) = 4{x}_{1}x3−x2=2(x2−x1)=4x1 ,使 f(x1)=f(x2)=f(x3)>0f\left( {x}_{1}\right) = f\left( {x}_{2}\right) = f\left( {x}_{3}\right) > 0f(x1)=f(x2)=f(x3)>0 ,则 φ\varphiφ 的值为（ ）A. −π6- \frac{\pi }{6}−6πB. π6\frac{\pi }{6}6πC. −π3- \frac{\pi }{3}−3πD. π3\frac{\pi }{3}3π