对于正数 a,ba,ba,b ,有 (2ab+1)(a+b)=6ab\left( {{2ab} + 1}\right) \left( {a + b}\right) = {6ab}(2ab+1)(a+b)=6ab , 则 a+ba + ba+b 的取值范围是（ ）A. (0,1](0,1\rbrack(0,1]B. [1,3]\left\lbrack {1,\sqrt{3}}\right\rbrack[1,3]C. [1,2]\left\lbrack {1,2}\right\rbrack[1,2]D. [2,+∞]\left\lbrack {2, + \infty }\right\rbrack[2,+∞]