已知双曲线 C:x2a2−y2b2=1(a>0,b>0)C : \frac{{x}^{2}}{{a}^{2}} - \frac{{y}^{2}}{{b}^{2}} = 1\left( {a > 0,b > 0}\right)C:a2x2−b2y2=1(a>0,b>0) 满足 ba=52\frac{b}{a} = \frac{\sqrt{5}}{2}ab=25 ,且与椭圆 x212+y23=1\frac{{x}^{2}}{12} + \frac{{y}^{2}}{3} = 112x2+3y2=1 有公共焦点,则双曲线 CCC 的方程为( )A. x24−y23=1\frac{{x}^{2}}{4} - \frac{{y}^{2}}{3} = 14x2−3y2=1B. x28−y210=1\frac{{x}^{2}}{8} - \frac{{y}^{2}}{10} = 18x2−10y2=1C. x25−y24=1\frac{{x}^{2}}{5} - \frac{{y}^{2}}{4} = 15x2−4y2=1D. x24−y25=1\frac{{x}^{2}}{4} - \frac{{y}^{2}}{5} = 14x2−5y2=1