设函数 f(x)=a(x+1)2−1,g(x)=cosx+2axf\left( x\right) = a{\left( x + 1\right) }^{2} - 1,g\left( x\right) = \cos x + {2ax}f(x)=a(x+1)2−1,g(x)=cosx+2ax ,当 x∈(−1,1)x \in \left( {-1,1}\right)x∈(−1,1) 时,曲线 y=f(x)y = f\left( x\right)y=f(x) 与 y=g(x)y = g\left( x\right)y=g(x) 恰有一个交点,则 a=a =a= ( )A. -1 B. 12\frac{1}{2}21 C. 1 D. 2