设函数 f(x)=2x−cosxf\left( x\right) = {2x} - \cos xf(x)=2x−cosx , {an}\left\{ {a}_{n}\right\}{an} 是公差为 π8\frac{\pi }{8}8π 的等差数列, f(a1)+f(a2)+⋯+f(a5)=5πf\left( {a}_{1}\right) + f\left( {a}_{2}\right) + \cdots + f\left( {a}_{5}\right) = {5\pi }f(a1)+f(a2)+⋯+f(a5)=5π ,则 [f(a3)]2−a1a5={\left\lbrack f\left( {a}_{3}\right) \right\rbrack }^{2} - {a}_{1}{a}_{5} =[f(a3)]2−a1a5=A. 0B. 116π2\frac{1}{16}{\pi }^{2}161π2 C. 18π2\frac{1}{8}{\pi }^{2}81π2 D. 1316π2\frac{13}{16}{\pi }^{2}1613π2