若曲线 y=ln2xy = \ln {2x}y=ln2x 在点 P(x1,y1)P\left( {{x}_{1},{y}_{1}}\right)P(x1,y1) 处的切线与曲线 y=e2xy = {\mathrm{e}}^{2x}y=e2x 相切于点 Q(x2,y2)Q\left( {{x}_{2},{y}_{2}}\right)Q(x2,y2) ,则 12x1−1+x2=\frac{1}{2{x}_{1} - 1} + {x}_{2} =2x1−11+x2= ___.