已知函数 f(x)=(x−1)ex−xlnxf\left( x\right) = \left( {x - 1}\right) {\mathrm{e}}^{x} - x\ln xf(x)=(x−1)ex−xlnx ,若 ∀x1,x2∈(0,+∞)\forall {x}_{1},{x}_{2} \in \left( {0, + \infty }\right)∀x1,x2∈(0,+∞) 且 x1≠x2{x}_{1} \neq {x}_{2}x1=x2 ,有 f(x1)−f(x2)x12−x22>a\frac{f\left( {x}_{1}\right) - f\left( {x}_{2}\right) }{{x}_{1}^{2} - {x}_{2}^{2}} > ax12−x22f(x1)−f(x2)>a 恒成立,则实数 aaa 的取值范围是___.