设数列 {an}\left\{ {a_n}\right\}{an} 满足 a1=3,an+1=3an−4n{a}_{1} = 3,{a}_{n + 1} = 3{a}_{n} - {4n}a1=3,an+1=3an−4n .(1)计算 a2,a3{a}_{2},{a}_{3}a2,a3 ,猜想 {an}\{ {a_n}\}{an} 的通项公式并加以证明;(2)求数列 {2nan}\{ {2^n a_n}\}{2nan} 的前 nnn 项和 Sn{S_n}Sn .