设点 A(−2,0)A\left( {-2,0}\right)A(−2,0) , B(−12,0)B\left( {-\frac{1}{2},0}\right)B(−21,0) , C(0,1)C\left( {0,1}\right)C(0,1) ,若动点 PPP 满足 ∣PA∣=2∣PB∣\left| {PA}\right| = 2\left| {PB}\right|∣PA∣=2∣PB∣ ,且 AP→=λAB→+μAC→\overrightarrow{AP} = \lambda \overrightarrow{AB} + \mu \overrightarrow{AC}AP=λAB+μAC ,则 λ+2μ\lambda + {2\mu }λ+2μ 的最大值为___.