在平面四边形 ABCD{ABCD}ABCD 中,若 AB⊥BC,AD⊥DC{AB}\bot {BC},{AD}\bot {DC}AB⊥BC,AD⊥DC ,且 AB=1,AD=3{AB} = 1,{AD} = 3AB=1,AD=3 ,则 AC→⋅BD→=\overrightarrow{AC} \cdot \overrightarrow{BD} =AC⋅BD= ()A. -8B. 8C. 10D. 3