如图,在三棱柱 ABC−A1B1C1{ABC} - {{A}_{1}{B}_{1}{C}_{1}}ABC−A1B1C1 中,平面 ACC1A1⊥{AC}{C}_{1}{A}_{1}\botACC1A1⊥ 平面 AA1B1BA{A}_{1}{B}_{1}BAA1B1B ,四边形 ACC1A1{AC}{C}_{1}{A}_{1}ACC1A1 是矩形, AA1B1BA{A}_{1}{B}_{1}BAA1B1B 是菱形, MMM , NNN 分别是 AB1A{B}_{1}AB1 , A1C{A}_{1}CA1C 的中点, AB=2AC{AB} = {2AC}AB=2AC , ∠A1AB=120∘\angle {A}_{1}{AB} = {120}^{ \circ }∠A1AB=120∘ . (1) 求证: AB1⊥A{B}_{1} \botAB1⊥ 平面 A1BC1{A}_{1}B{C}_{1}A1BC1 ;(2) 求二面角 A−MN−A1A - {MN} - {A}_{1}A−MN−A1 的正弦值.